Optimal. Leaf size=75 \[ \frac{\sqrt{\sin (2 a+2 b x)} \csc (a+b x) F\left (\left .a+b x-\frac{\pi }{4}\right |2\right ) \sqrt{d \tan (a+b x)}}{2 b}-\frac{d \sin (a+b x)}{b \sqrt{d \tan (a+b x)}} \]
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Rubi [A] time = 0.0901895, antiderivative size = 75, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.21, Rules used = {2598, 2601, 2573, 2641} \[ \frac{\sqrt{\sin (2 a+2 b x)} \csc (a+b x) F\left (\left .a+b x-\frac{\pi }{4}\right |2\right ) \sqrt{d \tan (a+b x)}}{2 b}-\frac{d \sin (a+b x)}{b \sqrt{d \tan (a+b x)}} \]
Antiderivative was successfully verified.
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Rule 2598
Rule 2601
Rule 2573
Rule 2641
Rubi steps
\begin{align*} \int \sin (a+b x) \sqrt{d \tan (a+b x)} \, dx &=-\frac{d \sin (a+b x)}{b \sqrt{d \tan (a+b x)}}+\frac{1}{2} \int \csc (a+b x) \sqrt{d \tan (a+b x)} \, dx\\ &=-\frac{d \sin (a+b x)}{b \sqrt{d \tan (a+b x)}}+\frac{\left (\sqrt{\cos (a+b x)} \sqrt{d \tan (a+b x)}\right ) \int \frac{1}{\sqrt{\cos (a+b x)} \sqrt{\sin (a+b x)}} \, dx}{2 \sqrt{\sin (a+b x)}}\\ &=-\frac{d \sin (a+b x)}{b \sqrt{d \tan (a+b x)}}+\frac{1}{2} \left (\csc (a+b x) \sqrt{\sin (2 a+2 b x)} \sqrt{d \tan (a+b x)}\right ) \int \frac{1}{\sqrt{\sin (2 a+2 b x)}} \, dx\\ &=-\frac{d \sin (a+b x)}{b \sqrt{d \tan (a+b x)}}+\frac{\csc (a+b x) F\left (\left .a-\frac{\pi }{4}+b x\right |2\right ) \sqrt{\sin (2 a+2 b x)} \sqrt{d \tan (a+b x)}}{2 b}\\ \end{align*}
Mathematica [C] time = 0.96188, size = 57, normalized size = 0.76 \[ \frac{\cos (a+b x) \sqrt{d \tan (a+b x)} \left (\sqrt{\sec ^2(a+b x)} \, _2F_1\left (\frac{1}{4},\frac{1}{2};\frac{5}{4};-\tan ^2(a+b x)\right )-1\right )}{b} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.14, size = 190, normalized size = 2.5 \begin{align*} -{\frac{\sqrt{2} \left ( \cos \left ( bx+a \right ) -1 \right ) \left ( \cos \left ( bx+a \right ) +1 \right ) ^{2}}{2\,b \left ( \sin \left ( bx+a \right ) \right ) ^{4}} \left ( \sin \left ( bx+a \right ){\it EllipticF} \left ( \sqrt{-{\frac{\cos \left ( bx+a \right ) -1-\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}},{\frac{\sqrt{2}}{2}} \right ) \sqrt{{\frac{\cos \left ( bx+a \right ) -1}{\sin \left ( bx+a \right ) }}}\sqrt{{\frac{\cos \left ( bx+a \right ) -1+\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}}\sqrt{-{\frac{\cos \left ( bx+a \right ) -1-\sin \left ( bx+a \right ) }{\sin \left ( bx+a \right ) }}}+ \left ( \cos \left ( bx+a \right ) \right ) ^{2}\sqrt{2}-\cos \left ( bx+a \right ) \sqrt{2} \right ) \sqrt{{\frac{\sin \left ( bx+a \right ) d}{\cos \left ( bx+a \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d \tan \left (b x + a\right )} \sin \left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\sqrt{d \tan \left (b x + a\right )} \sin \left (b x + a\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d \tan{\left (a + b x \right )}} \sin{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d \tan \left (b x + a\right )} \sin \left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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